Question

How do you find the derivative for `2x^4-1`?

Answer 1

`f(x) = 2x^4 - 1 = g(x) + h(x)`, where `g(x) = 2x^4` and `h(x) = -1`

`f'(x) = g'(x) + h'(x) = (2x^4)' + (-1)' = 4*2x^(4-1) + 0 = 8x^3`.