How do you factor #16x^2=56x#?

1 Answer
Jul 1, 2015

#8x(2x-7)=0#

Explanation:

We will move the right-hand side to the left-hand side :

#16x^2 = 56x# <=> #16x^2 - 56x = 0#

After that, we have to find the common factor inside the subtraction :

#16x^2 = color(red)(2*2*2)*2*x*color(green)x# and #56x = color(red)(2*2*2)*7*color(green)x#

Then the common factor of #16x^2# and #56x# is #color(red)(2*2*2)*color(green)x = 8x# and so : #16x^2 = 8x * 2x# and #56x = 8x *7#

Therefore, the factorization of #16x^2-56x=0# is :
#8x*2x - 8x*7 = 0# <=> #8x.(2x-7)=0#

And now you can solve this equation with the property of multiplication!