How do you prove the identity $cot (x) + sec (x) = \frac{cos (x) + tan (x)}{sin (x)}$ $cot(x)+sec(x)=(cos(x)+tan(x))/sin(x)$ ?

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How do you prove the identity $cot (x) + sec (x) = \frac{cos (x) + tan (x)}{sin (x)}$ $cot(x)+sec(x)=(cos(x)+tan(x))/sin(x)$ ?

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Answer 1 · 2015-08-12T13:26:45

$cot x + sec x = \frac{cos x}{sin x} + \frac{1}{cos x} = \frac{cos x}{sin x} + \frac{sin x}{sin x cos x} = \frac{cos x + tan x}{sin x}$ $cot x + sec x = cos x/sin x + 1/cos x = cos x/sin x + sin x/(sin x cos x) = (cos x + tan x)/sin x$

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How do you prove the identity $cot (x) + sec (x) = \frac{cos (x) + tan (x)}{sin (x)}$ $cot(x)+sec(x)=(cos(x)+tan(x))/sin(x)$ ?

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How do you prove the identity cot(x)+sec(x)=cos(x)+tan(x)sin(x)cot(x)+sec(x)=(cos(x)+tan(x))/sin(x)?

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How do you prove the identity $cot (x) + sec (x) = \frac{cos (x) + tan (x)}{sin (x)}$ $cot(x)+sec(x)=(cos(x)+tan(x))/sin(x)$ ?