How do you evaluate the sum represented by #sum_(k=50)^300k^3#?

3 Answers
Aug 29, 2015

The question is unclear, but if you meant #sum_(n=1)^300 k^3# with #k = "(constant) " 50#,
then
#sum_(n=1)^300 k^3 = 300*(50)^3 = 37500000#

Explanation:

If #k=50# then #k^3 = 125000# (a constant)

#sum_(n=1)^p c # for any constant #c#
#color(white)("XXXX")= p*c#

Aug 29, 2015

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Explanation:

This is the question. i don't understand this.

You can read this "the sum, from k equals 50 to 300, of k to the third"

or "the sum, of k to the third", from k equals 50 to 300"

There are other ways to say it as well, but these two are enough to start.

(for example you could say "from k = 50 to k= 300"

Aug 29, 2015

Use formula for #sum_(k=1)^n k^3# to find #sum_(k=50)^300 k^3 = 2037021875#

Explanation:

Use #sum_(k=1)^n k^3 = (n^2+n)^2/4# (proved in another question recently).

See: http://socratic.org/questions/how-do-you-evaluate-the-sum-represented-by-with-n-3-any-examples

Then:

#sum_(k=50)^300 k^3 = sum_(k=1)^300 k^3 - sum_(k=1)^49 k^3#

#=(300^2+300)^2/4 - (49^2+49)^2/4#

#=90300^2/4 - 2450^2/4#

#=45150^2-1225^2#

#=2038522500-1500625#

#=2037021875#