How do you evaluate the sum represented by sum_(k=50)^300k^3?

3 Answers
Aug 29, 2015

The question is unclear, but if you meant sum_(n=1)^300 k^3 with k = "(constant) " 50,
then
sum_(n=1)^300 k^3 = 300*(50)^3 = 37500000

Explanation:

If k=50 then k^3 = 125000 (a constant)

sum_(n=1)^p c for any constant c
color(white)("XXXX")= p*c

Aug 29, 2015

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Explanation:

This is the question. i don't understand this.

You can read this "the sum, from k equals 50 to 300, of k to the third"

or "the sum, of k to the third", from k equals 50 to 300"

There are other ways to say it as well, but these two are enough to start.

(for example you could say "from k = 50 to k= 300"

Aug 29, 2015

Use formula for sum_(k=1)^n k^3 to find sum_(k=50)^300 k^3 = 2037021875

Explanation:

Use sum_(k=1)^n k^3 = (n^2+n)^2/4 (proved in another question recently).

See: http://socratic.org/questions/how-do-you-evaluate-the-sum-represented-by-with-n-3-any-examples

Then:

sum_(k=50)^300 k^3 = sum_(k=1)^300 k^3 - sum_(k=1)^49 k^3

=(300^2+300)^2/4 - (49^2+49)^2/4

=90300^2/4 - 2450^2/4

=45150^2-1225^2

=2038522500-1500625

=2037021875