How do you solve .05(1.15)^x = 5? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer dani83 Sep 2, 2015 x = log_1.15 100 Explanation: log a^n = n log a log_a b = log_c b/log_c a 0.05(1.15)^x = 5 1.15^x = 100 xlog 1.15 = log 100 x = log_1.15 100 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 3884 views around the world You can reuse this answer Creative Commons License