How do you solve $log (x-1)^2 = log (-5x-1)$ ?

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Answer 1 · 2015-09-02T16:20:14

$x = -1$ or $x = -2$

$log (x-1)^2 = log (-5x-1)$
$x^2-2x+1 = -5x-1$
$x^2+3x+2 = 0$
$(x+1)(x+2) = 0$
$x = -1$ or $x = -2$

How do you solve log (x-1)^2 = log (-5x-1)log (x-1)^2 = log (-5x-1)?