How do you find the length of side c for the triangle with dimensions A = 57° , a = 11, b = 10?

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How do you find the length of side c for the triangle with dimensions A = 57° , a = 11, b = 10?

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Answer 1 · 2015-09-12T13:15:19

Find Angle B, then, with A and B we can find angle C. Knowing C will allow us to find c.

Explanation:

$sin B = \frac{10}{11} {sin 57}^{\circ}$ $sinB = 10/11 sin57^@$

So $B \approx {49.7}^{\circ}$ $B ~~ 49.7^@$

$C = 180^{\circ} - A - B \approx {73.3}^{\circ}$ $C = 180^@ -A - B ~~ 73.3^@$

$c = \frac{11}{{sin 57}^{\circ}} {sin 73.3}^{\circ} \approx 12.6$ $c = 11/(sin57^@) sin73.3^@ ~~ 12.6$

Answer 2 · 2015-09-12T13:51:24

It is $c = 10, 059$ $c=10,059$

Explanation:

We can use the law of cosines hence

$c^{2} = a^{2} + b^{2} - 2 a b cos A \Rightarrow c^{2} = {(11)}^{2} + {(10)}^{2} - 2 \cdot 10 \cdot 11 \cdot cos (57) \Rightarrow c = 10, 059$ $c^2=a^2+b^2-2abcosA=>c^2=(11)^2+(10)^2-2*10*11*cos(57)=> c=10,059$

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How do you find the length of side c for the triangle with dimensions A = 57° , a = 11, b = 10?

2 Answers

Explanation:

Explanation:

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