Question

How do you solve `Cos theta Tan theta+sqrt(3)Cos theta=0` for [0,2pi]?

Answer 1

`theta = (5pi)/6` and `(11pi)/6`

Explanation:

`costheta * (sintheta /costheta) + sqrt3costheta =0`

You know that `tantheta=sintheta /costheta`, which means that you have

`sintheta + sqrt3costheta =0`

`sintheta = - sqrt3 * costheta`

`tantheta =-sqrt3` for `[0,2pi]`,

`theta = pi - (pi/3)` and `2pi - (pi/3)`

`theta = (5pi)/6` and `(11pi)/6`