How do you solve Cos theta Tan theta+sqrt(3)Cos theta=0cosθtanθ+√3cosθ=0 for [0,2pi]?
1 Answer
Sep 26, 2015
Explanation:
costheta * (sintheta /costheta) + sqrt3costheta =0cosθ⋅(sinθcosθ)+√3cosθ=0
You know that
sintheta + sqrt3costheta =0sinθ+√3cosθ=0
sintheta = - sqrt3 * costhetasinθ=−√3⋅cosθ
tantheta =-sqrt3tanθ=−√3 for[0,2pi][0,2π] ,
theta = pi - (pi/3)θ=π−(π3) and2pi - (pi/3)2π−(π3)
theta = (5pi)/6θ=5π6 and(11pi)/611π6