How do you find the domain & range for f(x)=sqrt(tan(2x+π))?

1 Answer
Sep 30, 2015

The range is (- oo , oo ) and domain is (- pi/2 , pi/4 )

Explanation:

For domain and range this must be included in the answer.
Y = sqrt tan(2x + pi) => 0 < tan (2x + pi ) < oo =>
0 < 2x + pi <pi/2 => -pi < 2x < - pi + pi/2 => -pi < 2x <-pi/2 =>
-pi/2 < x < -pi/4