How do you solve $4 x - 30 > - 3 x + 12$ $4x-30> -3x+12$ ?

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How do you solve $4 x - 30 > - 3 x + 12$ $4x-30> -3x+12$ ?

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Answer 1 · 2015-10-03T00:40:03

Refer to explanation

Explanation:

What you got is called inequality .You need to find the values of variable x that make the inequality true. Hence

$4 x - 30 > - 3 x + 12$ $4x-30 > -3x+12$
Move -30 to other side and change sign.
$4 x > 30 - 3 x + 12$ $4x>30-3x+12$
Move -3x to other side and change sign as well
$4 x + 3 x > 30 + 12$ $4x+3x>30+12$
Now add in both sides
$7 x > 42$ $7x>42$
Divide by 7 both sides
$\frac{7 x}{7} > \frac{42}{7}$ $(7x)/7>(42)/7$
Simplify
$x > 6$ $x>6$

Hence the values of x that satisfy the inequality belong to interval
$(6, + \infty)$ $(6,+oo)$

Answer 2 · 2015-10-03T00:42:47

The answer is $x > 6$ $x>6$ .

Explanation:

$4 x - 30 > - 3 x + 12$ $4x-30> -3x+12$

Solve as if this were an equation.

Add $30$ $30$ to both sides of the inequality.

$4 x > - 3 x + 12 + 30 =$ $4x> -3x+12+30=$

$4 x > - 3 x + 42$ $4x> -3x+42$

Add $3 x$ $3x$ to both sides of the inequality.

$4 x + 3 x > 42 =$ $4x+3x>42=$

$7 x > 42$ $7x>42$

Divide both sides by $7$ $7$ .

$x > \frac{42}{7} =$ $x>42/7=$

$x > 6$ $x>6$

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How do you solve $4 x - 30 > - 3 x + 12$ $4x-30> -3x+12$ ?

2 Answers

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