Question

How do you differentiate `y=(4x^2+5)(3x-5)`?

Answer 1

Start by simplifying the value of `y`.

Explanation:

So that gives us; `12x^3-20x^2+15x-25`

Now for

`dy/dx = 3(12) x^2 - 2(20)x +15`

`= 36x^2-40x+15.`

And you end up with a quadratic equation
Classic question.