How do you factor #2x^2+3x+4#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Omar T. Oct 28, 2015 This cannot be factored Explanation: There are no numbers which #4# and #2# can multiply together and add/subtract to #3#. However, it can be solved by using the quadratic formula #(-b+-sqrt(b^2-4(a)(c)))/(2(a))# where #a# is #2#, #b# is #3# and #c# is #4# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 10827 views around the world You can reuse this answer Creative Commons License