How do you factor $2 x^{2} + 7 x + 3 = 0$ $2x^2 + 7x + 3 = 0$ ?

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Answer 1 · 2015-10-28T23:54:13

$(x + 3) (2 x + 1)$ $(x+3)(2x+1)$

Our factorization will take the form

$(a + b) (c + d)$ $(a+b)(c+d)$

These take practice. In this case I started of as follows

From the FOIL method I know that the last product has to be
$3$ $3$ so the factors are $1$ $1$ and $3$ $3$

$(a + 3) (b + 1)$ $(a+3)(b+1)$

The middle term of your original expression is $7 x$ $7x$

Therefore

$(x + 3) (2 x + 1)$ $(x+3)(2x+1)$

How do you factor 2x2+7x+3=02x^2 + 7x + 3 = 0?