How do you factor $2x^2 + 7x + 3 = 0$ ?

Question

1664 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-28T23:54:13

$(x+3)(2x+1)$

Our factorization will take the form

$(a+b)(c+d)$

These take practice. In this case I started of as follows

From the FOIL method I know that the last product has to be
$3$ so the factors are $1$ and $3$

$(a+3)(b+1)$

The middle term of your original expression is $7x$

Therefore

$(x+3)(2x+1)$

How do you factor 2x^2 + 7x + 3 = 02x^2 + 7x + 3 = 0?