What is the derivative of #f(x)=sec(ln(1/x))#?

1 Answer
Nov 13, 2015

The derivative would be #-1/x . sec(ln(1/x)). tan(ln(1/x))#

Explanation:

Always treat problem such as this like the following. Break this problem into three parts:

# w = sec(y) # where #y= ln u# where #u=1/x# so the derivative of this function would be:

# f'(x) = u' . y ' . w' #

Derivate the functions separately and then multiply them with each other. Finally substitute the with the original variables.

Hope that helps,
Cheers.