How do you factor $35 a^{3} b c^{2} - 45 a^{2} b^{2} c$ $35a^3bc^2-45a^2b^2c$ ?

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Answer 1 · 2015-11-14T15:28:41

$5 a^{2} b c (7 a c - 9 b) = 0$ $5a^2bc(7ac-9b)=0$

$35 a^{3} b c^{2} - 45 a^{2} b^{2} c = 0$ $35a^3bc^2-45a^2b^2c=0$
Factor out
$5 a^{2} b c (7 a c - 9 b) = 0$ $5a^2bc(7ac-9b)=0$

How do you factor 35a^3bc^2-45a^2b^2c35a3bc2−45a2b2c35a^3bc^2-45a^2b^2c?