Question #f6c62

1 Answer
Nov 17, 2015

Let A be the event that the die shows an even number first and B the event that the second throw results in an odd number. Required P(A #nn# B) = P(A) P(B) = 1/2 #xx# 1/2 = 1/4.

Explanation:

A and B are independent events and hence P (A #nn# B) = P(A) P(B)