Question #0d7b5

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Answer 1 · 2015-12-12T04:31:42

$x = i$ $x=i$

First you want to factor. You can factor out the 3.

$(3) (x^{2} + 1) = 0$ $(3)(x^2+1)=0$

Divide both sides by three

$\frac{(3) (x^{2} + 1)}{3} = \frac{0}{3}$ $((3)(x^2+1))/3=0/3$

$x^{2} + 1 = 0$ $x^2+1=0$

Solve for x

$x^{2} = - 1$ $x^2=-1$

$\sqrt{x^{2}} = \sqrt{- 1}$ $sqrt(x^2)=sqrt(-1)$

$x = \sqrt{- 1}$ $x=sqrt(-1)$

$x = i$ $x=i$