How do you find the inverse of f(x)=x2x+2?

1 Answer
Dec 13, 2015

f1(x)=2(x+1)1x

Explanation:

f(x)=x2x+2

y=x2x+2

Switch x for y and y for x

x=y2y+2

Multiply both side by y+2

(y+2)x=(y2y+2)(y+2)

Distribute

xy+2x=y2

Bring all "y" term to one side and factor

2x+2=yxy

Factor, and solve for y

2(x+1)=y(1x)

2(x+1)1x=y

Replace y with inverse notation f1(x)

2(x+1)1x=f1(x)