What is the vertex form of y=x23x+5?

1 Answer
Dec 25, 2015

There are many ways of finding the vertex form of this type quadratic functions. An easy method is given below.

Explanation:

If we have y=ax2+bx+c and to write it in vertex form we do the following steps.

If the vertex is (h,k) then h=(b2a) and k=a(h)2+b(h)+c

The vertex form is y=a(x-h)^2 + k.

Now let us use the same with our question.

y=x23x+5

Comparing it with y=ax2+bx+c we get a=1, b=3, c=5

h=b2a
h=32(1)
h=32

k=(32)23(32)+5
k=94+92+5
k=+94+5
k=94+204
k=294

y=(x(32))2+294

y=(x+32)2+294 is the vertex form