How do solve the following linear system?: $4 y - 16 = x, x - 2 y = 8$ $4y-16=x , x-2y=8$ ?

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Answer 1 · 2015-12-29T05:20:46

Via substitution

You have two equations:

$x = 4 y - 16$ $x = 4y -16$ & $x - 2 y = 8$ $x -2y = 8$

Because $x$ $x$ and $y$ $y$ are in both equations we can substitute one into the other.

Substitute the first equation into the second:

$(4 y - 16) - 2 y = 8$ $(4y -16) - 2y = 8$

Now group your $y$ $y$ terms:

$- 16 + 2 y = 8$ $-16 + 2y = 8$

Now solve for $y$ $y$ :

$2 y = 24$ $2y = 24$ $\to$ $->$ $y = \frac{24}{2}$ $y = 24/2$ $\to$ $->$ $y = ...$ You do the rest!

Don't forget to substitute your answer into the original equations to check it is correct.

How do solve the following linear system?: 4y-16=x , x-2y=8 4y−16=x,x−2y=8 4y-16=x , x-2y=8 ?