How much distance does a car with an acceleration of $4.0$ $4.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ travel as it goes from $10$ $10$ $m$ $m$ $/$ $/$ $s$ $s$ to $30$ $30$ $m$ $m$ $/$ $/$ $s$ $s$ ?

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How much distance does a car with an acceleration of $4.0$ $4.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ travel as it goes from $10$ $10$ $m$ $m$ $/$ $/$ $s$ $s$ to $30$ $30$ $m$ $m$ $/$ $/$ $s$ $s$ ?

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Answer 1 · 2016-01-07T04:22:29

100 m

Explanation:

Use the third equation of motion (time independent)
$v^{2}$ $v^2$ - $u^{2}$ $u^2$ = $2 a x$ $2ax$
and the variables $v, u$ $v, u$ and $a$ $a$
Final velocity $v = 30 m s^{- 1}$ $v = 30 m s^-1$
Initial velocity $u = 10 m s^{- 1}$ $u = 10 m s^-1$
acceleration $a = 4 m s^{- 2}$ $a = 4 m s^-2$

$S o l u t i o n :$ $Solution:$

$v^{2}$ $v^2$ - $u^{2}$ $u^2$ = $2 a x$ $2ax$
$30^{2}$ $30^2$ - $10^{2}$ $10^2$ = $2 \times 4 \times x$ $2 xx 4 xx x$
$900 - 100 = 8 x$ $900 - 100 = 8 x$
$800 = 8 x$ $800 = 8 x$
or $100$ $100$ meters

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How much distance does a car with an acceleration of $4.0$ $4.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ travel as it goes from $10$ $10$ $m$ $m$ $/$ $/$ $s$ $s$ to $30$ $30$ $m$ $m$ $/$ $/$ $s$ $s$ ?

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How much distance does a car with an acceleration of $4.0$ $4.0$ $m$ $m$ $/$ $/$ $s^{2}$ $s^2$ travel as it goes from $10$ $10$ $m$ $m$ $/$ $/$ $s$ $s$ to $30$ $30$ $m$ $m$ $/$ $/$ $s$ $s$ ?