What is $(x^{3} + 3 x^{2} + 3 x + 4) \div (x + 2)$ $(x^3+ 3x^2+3 x+ 4)-:( x+2)$ ?

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Answer 1 · 2016-01-10T12:32:54

$x^{2} + x + 1 + \frac{2}{x + 2}$ $x^2+x+1+2/(x+2)$

$x^{3} + 3 x^{2} + 3 x + 4 = (x + 2) (a x^{2} + b x + c) + r$ $x^3+3x^2+3x+4=(x+2)(ax^2+bx+c)+ r$

By expanding the brackets and equating coefficients you get:

$a = 1, b = 1, c = 1, r = 2$ $a=1, b=1, c=1, r=2$

What is (x3+3x2+3x+4)÷(x+2)(x^3+ 3x^2+3 x+ 4)-:( x+2)?