What is the derivative of sqrt x^2?

2 Answers
Jan 11, 2016

x/sqrt(x^2)

Explanation:

first rewrite sqrt(x^2) = (x^2)^(1/2)

now differentiate using the chain rule :

1/2(x^2)^(-1/2).d/dx(x^2)

= 1/2(x^2)^(-1/2) .(2x) =x( x^2)^(-1/2) =x/(x^2)^(1/2) = x/sqrt(x^2

It is usual to give answer in the same form as question.

Jan 11, 2016

Assuming the question is asking (sqrt(x))^2 or sqrt((x^2)), which is then simplified to x, the answer is 1.

Explanation:

(sqrt(x))^2 can be rewritten as (x^(1/2))^(2). Multiplying the exponents gives x^1, which is just x.

The definition of d/dx(x) = 1 is typically memorized, though you can always use the power rule to get the same answer:

d/dx(x) = d/dx(x^1) = (1)x^(1-1) = (1)(x^0) = (1)(1) = 1

If the problem were instead asking d/dx(sqrt(x)), with the 2 indicating that it's the second root, then the same power rule approach would be taken:

d/dx(sqrt(x)) = d/dx(x^(1/2)) = (1/2)x^(1/2 - 1) = (1/2)x^(-1/2) = 1/(2x^(1/2))
=1/(2sqrtx)