How do you solve #12x + 16 <= 10x#?

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Answer 1 · 2016-01-22T11:41:06

#12x + 16 <= 10x #

#12x - 10x <= -16 #

# 2x <= -16 #

# x <= -16/2 #

# x <= -8 #

So, #x # is less than or equal to -8.