Assume the series 10+18+26... continues for 200 terms. What is the sum?

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Answer 1 · 2016-01-25T17:54:44

#a_2-a_1=18-10=8#
#a_3-a_2=26-18=8#

#implies# This is an arithmetic series .

#implies# common difference#=d=8#
first term#=a_1=10#

The sum of arithmetic series is given by

#Sum=n/2{2a_1+(n-1)d}#

Where #n# is the number of terms, #a_1# is the first term and #d# is the common difference.

Here #a_1=10#, #d=8# and #n=200#

#implies Sum=200/2{2*10+(200-1)8}=100(20+199*8)=100(20+1592)=100*1612=161200#

Hence the sum is#161200#.