What is $\frac{\sqrt{108 x^{3}}}{\sqrt{3 x}}$ $sqrt(108x^3)/sqrt(3x)$ ?

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Answer 1 · 2016-01-31T19:45:22

This can be simplified to $6 x$ $6x$

Simplify the radical by breaking the radicand up into a product of known factors:
$\sqrt{108 x^{3}} = 6 x \sqrt{3 x}$ $sqrt(108x^3) = 6x sqrt(3x)$

Our equation now looks like this:
$\frac{6 x \sqrt{3 x}}{\sqrt{3 x}}$ $(6x sqrt(3x))/(sqrt(3x))$

We can cancel the two $\sqrt{3 x}$ $sqrt(3x)$

So we are left with $6 x$ $6x$

What is sqrt(108x^3)/sqrt(3x)√108x3√3xsqrt(108x^3)/sqrt(3x)?