Question

How do you solve the following system of equations?: `x+y= -2 , 4x+3y=8`?

Answer 1

the answer: `x=14` and `y = -16`

Explanation:

In the two equations, get `y` alone. So you have:

`y= -x-2` and

`y= -4/3 x +8/3`.

Then you set the two equations equal to each other:

`-x-2= -4/3 x +8/3`.

Then you solve for `x`, and you get `x=14`. You then substitute `14` into both equations to get `y`, and then you have your coordinates.

Answer 2

Solve by substitution and elimination:

`x+y=-2`

`4x+3y=8`

We can eliminate `4x` from the second equation by `x` from the first equation if we multiply it by `-4` to get `-4x`:

`rarr-4(x+y=-2)`

`rarr-4x-4y=8`

Now add both of the equations:

`rarr(-4x-4y=8)+(4x+3y=8)`

`rarr-1y=16`

`rarr-y=16`

So,if `-y =16` then ,`y =-16`

Now substitute the value of #y # to the first equation:

`x+(-16)=-2`

`x-16=-2`

`x=-2+16=14`

So,`(x,y)=(14,-16)`

You can check the answer and it will be correct! :)