Simplify $- \frac{x^{2} - 6 x + 5}{x^{2} - 10 x + 25}$ $-(x^2-6x+5)/(x^2-10x+25)$ ?

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Answer 1 · 2016-02-08T21:37:15

$\frac{1 - x}{x - 5}$ $(1-x)/(x-5)$

To simplify the expression, one should factorize both the expressions in numerator and denominator.

Factors of numerator are $- (x - 5) (x - 1)$ $-(x-5)(x-1)$ .

Factors of denominator are ${(x - 5)}^{2}$ $(x-5)^2$

Hence it could be written as

$- \frac{(x - 5) (x - 1)}{{(x - 5)}^{2}}$ $-((x-5)(x-1))/(x-5)^2$ or $- \frac{x - 1}{x - 5}$ $-(x-1)/(x-5)$ or

$\frac{1 - x}{x - 5}$ $(1-x)/(x-5)$

Simplify −x2−6x+5x2−10x+25-(x^2-6x+5)/(x^2-10x+25)?