Question

How much power is required to lift an object of weight `595` newtons by `3.15` meters in `15.2` seconds?

Answer 1

Power output is `123.306` watts.

Explanation:

Potential Energy (in Joules) `PE` gained is given by

`PE` = `m*g*h`, where `m` is mass in kilograms, `g` is acceleration due to gravity (`9.8` meters per `second^2`) and `h` is height in meters. We can also write this as `PE` = `w*h`, where `w` is weight in Newtons - as it is given in Newtons here. (Obviously `w=m*g`).

Power in watts is given by `(PE)/t`, where `t` is times in seconds.

Accordingly `PE` here is `595*3.15` or `1,874.25` and

Power output is `1874.25/15.2` or `123.306` watts.