How do you solve $22 -5(6v-1) = -63$ ?

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Answer 1 · 2016-02-13T20:32:33

$-1.2$

Follow the rule BODMAS so
1: $22 - 30v + 5= 63$
2: $-30v= 63-27$
3: $-30v=36$
4: $v=36 divide -30$
5: $v= -1.2$

Answer 2 · 2016-02-14T11:08:38

$color(green)(v=3$

$color(blue)(22-5(6v-1)=-63$

Use distributive property $color(orange)(a(b+c)=ab+ac$

$rarr22-30v+5=-63$

$rarr27-30v=-63$

Subtract $27$ both sides

$rarr-30v=-63-27$

$rarr-30v=-90$

$rarrcolor(green)(v=(-90)/-30=90/30=9/3=3$

How do you solve 22 -5(6v-1) = -6322 -5(6v-1) = -63?