How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?
1 Answer
Feb 29, 2016
4g
Explanation:
It works to (.45 * x grams) + (1.00 x 6 grams) = .78 (x+6 grams)
.45x + 6 = .78x +4.68
Simplify
.33x = 1.32
x=4
Source: Algebra.com
