Question #c8714

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Answer 1 · 2016-03-03T03:08:32

$556 . m^{2}$ $556.m^2$

First, divide it into rectangles.

$2 (17 m \cdot 10 m)$ $color(blue)( 2 (17 m * 10 m)$ rectangles

$2 (10 m \cdot 4 m)$ $color(orange)(2 (10 m * 4 m)$ rectangles

$2 (17 m \cdot 4 m)$ $color(red)(2 (17 m * 4 m)$ rectangles

After that, multiply them out:

$2 (170 m^{2}) = 2 \cdot 170 = 340 . m^{2}$ $color(blue)(2 (170 m^2) = 2*170 = 340 .m^2$

$2 (40 m^{2}) = 2 \cdot 40 = 80 . m^{2}$ $color(orange)(2 (40 m^2) = 2* 40 = 80. m^2$

$2 (68 m^{2}) = 2 \cdot 68 = 136 . m^{2}$ $color(red)(2 (68 m^2) = 2* 68 = 136. m^2$

Finally, add them together:

$\Rightarrow 340 + 80 + 136 = 556 . m^{2}$ $rArrcolor(green)(340+80+136=556.m^2$

Answer 2 · 2016-03-16T13:38:46

$556 . m^{2}$ $556.m^2$

This figure is a cuboid

Surface area of a cuboid $= 2 (b l + h l + b h)$ $=color(blue)(2(bl+hl+bh)$

Where

$b = b r e a d t h, h = h e i g h t, l = l$ $color(red)(b=breadth,h=height,l=l$ $e n g$ $color(red)(eng$ $t h$ $color(red)(th$

$color(orange)( :.h=4,l=17,b=10$

Substitute the values in the formula

$rarr2((10*17)+(4*17)+(10*4))$

$rarr2((170)+(68)+(40))$

$rarr2(278)$

$rArrcolor(green)(556.m^2$

Solution $=color(green)(ul bar (|556.m^2|)$