How do you solve the system $x + y = 2$ $x+y=2$ and $x - y = 4$ $x-y=4$ ?

Question

How do you solve the system $x + y = 2$ $x+y=2$ and $x - y = 4$ $x-y=4$ ?

1 Answer

Impact of this question

20287 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-08T00:20:49

The solution is $(3, - 1)$ $( 3, -1 )$

Explanation:

In this case the solution can be found by using the "elimination method". Looking at the two equations I see that you have $+ y$ $+y$ in equation one and $- y$ $-y$ in equation two. By adding the two equations together I will "eliminate" the $y$ $y$ variable and then I can solve for $x$ $x$ .

$x + y = 2$ $x + y = 2$
$x - y = 4$ $x - y = 4$

Add the two equation together and get:

$2 x = 6$ $2x = 6$

x = 3 Now substitute $3$ $3$ for $x$ $x$ in either equation and solve for $y$ $y$

$x + y = 2$ $x + y = 2$
$3 + y = 2$ $3 + y = 2$
$y = - 1$ $y = - 1$
The solution is $(3, - 1)$ $(3 , -1 )$
Now you can, and should, verify that your answer is correct by substituting the solution in the second equation. If it works out, you have the correct answer.
$x - y = 4$ $x - y = 4$
$3 - (- 1) = 4$ $3 - (-1) =4$
$4 = 4$ $4 = 4$

Science

Math

Humanities

... and beyond

How do you solve the system $x + y = 2$ $x+y=2$ and $x - y = 4$ $x-y=4$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the system x+y=2x+y=2 and x−y=4x-y=4?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the system $x + y = 2$ $x+y=2$ and $x - y = 4$ $x-y=4$ ?