How do you find the polar coordinate of (-1,1)?

1 Answer

Polar coordinates are (sqrt2,(3pi)/4)

Explanation:

Polar coordinates (r,theta) of rectangular coordinates (x,y) are given by r=sqrt(x^2+y^2) and theta=tan^(-1)(y/x).

Hence polar coordinates of (-1,1) are

(sqrt((-1)^2+1^2),tan^(-1)((-1)/1)) or

(sqrt((1+1)),tan^(-1)(-1)) or

(sqrt2,(3pi)/4)