How do you integrate x+4x2+2x+5dx using partial fractions?

1 Answer
Apr 1, 2016

12[lnx2+2x+5+3arctan(x+12)]+c

Explanation:

First split the integral into two parts:

x+1 is a scalable factor of the derivative of x2+2x+5, so divide x+4 by x+1

x+4x2+2x+5dx=x+1x2+2x+5dx+3x2+2x+5dx

Algebraic manipulation yields:
122x+2x2+2x+5dx+31(x+1)2+4dx
=12lnx2+2x+5+32arctan(x+12)+c
=12[lnx2+2x+5+3arctan(x+12)]+c