What is the diameter of a circle with area of $18pi$ $ft^2$ ?

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Answer 1 · 2016-04-03T16:43:02

$6sqrt2pi ft$

Area of a circle $= pir^2$

$18pi = pir^2$
$18 = r^2$
$r = sqrt18 = 3sqrt2$

Perimeter of a circle $= 2pir$

$2pir = 2pi * 3sqrt2$
$= 6sqrt2pi$

What is the diameter of a circle with area of 18pi18pi ft^2ft^2?