Is #f(x) =cotx-cosx# concave or convex at #x=pi/3#?
1 Answer
Apr 8, 2016
Explanation:
-
#f'(x)=-csc^2x+sinx#
#f'(x)=0=>-csc^2x+sinx=0#
#sinx=csc^2x#
#sinx=1/sin^2x=>sin^3x=1#
#sinx=1=>x=pi/2#
:. the function has a local maxima/minima at#x=pi/2# -
#f(pi/3)=cot(pi/3)-cos(pi/3)=0.077#
#f(pi/3)>0=>"the function is concave at " x=pi/3 # -
If you check the graph
#pi/2-=1.571=>pi/3-=1.05#
graph{cotx-cosx [-0.706, 1.902, -0.256, 1.048]}