Question #831dc

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Answer 1 · 2016-04-15T21:02:34

see below

#sec^2x-1=sin^2x/cos^2x#

Use the property #sec^2x=tan^2x+1#

LHS=Left hand side. RHS=Right hand side. We start with the left hand side and show that it equals the right hand side.

#LHS=sec^2x-1#

#=tan^2x#

#=sin^2x/cos^2x#

#=RHS#