Question

How do you solve `int_0^2 x^4+5x dx`?

Answer 1

`82/5`

Explanation:

First, take the antiderivative:
`[1/5x^5 + 5/2x^2]_0^2`

Then, evaluate:
`(1/5(2)^5 + 5/2(2)^2) - (0)`
`=32/5+10`
`=82/5`