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Question #ab32b

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May 6, 2016

$\frac{2}{\sqrt{3}}$ $2/sqrt(3)$ or $\frac{2 \sqrt{3}}{3}$ $(2sqrt3)/3$

Explanation:

$sec (\frac{π}{6}) = \frac{1}{cos (\frac{π}{6})}$ $sec (pi/6) = 1/ (cos (pi/6))$

$cos (\frac{π}{6}) = \frac{\sqrt{3}}{2}$ $cos (pi/6) = sqrt (3)/2$

$\frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}}$ $1/(sqrt(3)/2) = 2/sqrt3$

Rationalize the denominator by multiplying the numerator and denominator by $\sqrt{3}$ $sqrt3$

$\frac{2}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{2 \sqrt{3}}{3}$ $2/sqrt(3) * sqrt3/sqrt3 = (2sqrt3)/3$

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