What is the equation of a line that passes through $(-8, -3)$ and has a slope of $-4$ ?

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Answer 1 · 2016-05-19T15:29:03

$y = -4x-35$

Formula for slope is:

$m = (y_2 - y_1)/(x_2 - x_1)$

using this we have,

$-4 = (-3 - y)/(-8 - x)$

$rArr-4*(-8-x) = -3-y$

$rArr32+4x = -3-y$

by rearranging we have the equation of the line which passes through $(-8,-3)$ with slope $-4$

$y = -4x-35$

What is the equation of a line that passes through (-8, -3)(-8, -3) and has a slope of -4-4?