What is the equation of a line that passes through $(- 8, - 3)$ $(-8, -3)$ and has a slope of $- 4$ $-4$ ?

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Answer 1 · 2016-05-19T15:29:03

$y = - 4 x - 35$ $y = -4x-35$

Formula for slope is:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

using this we have,

$- 4 = \frac{- 3 - y}{- 8 - x}$ $-4 = (-3 - y)/(-8 - x)$

$\Rightarrow - 4 \cdot (- 8 - x) = - 3 - y$ $rArr-4*(-8-x) = -3-y$

$\Rightarrow 32 + 4 x = - 3 - y$ $rArr32+4x = -3-y$

by rearranging we have the equation of the line which passes through $(- 8, - 3)$ $(-8,-3)$ with slope $- 4$ $-4$

$y = - 4 x - 35$ $y = -4x-35$

What is the equation of a line that passes through (-8, -3)(−8,−3)(-8, -3) and has a slope of -4−4-4?