How do you factor the trinomial #49x^2-21x+2#?

1 Answer
Jun 3, 2016

#(7x-1)(7x-2)#

Explanation:

You have a square number, 49 as your #x^2# coefficient. Therefore your factors within your parentheses are both going to start with # 7x# Your centre term has a negative coefficient and your last term is a positive. This indicates that the signs inside will both be negative. Lastly, negative 1 multiplied by negative 2 gives you # +2#

If you expand it as a check, you should get back to your original trinomial.