If $h (n) = - 2 n^{3} + 1$ $h(n) = -2n^3 + 1$ and $g (n) = - n - 3$ $g(n) = -n-3$ , what is $h (- 2) + g (- 2)$ $h(-2) + g(-2)$ ?

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Answer 1 · 2016-06-05T09:35:15

16

let's substitute n by -2 in the first one
$h (- 2) = - 2 {(- 2)}^{3} + 1$ $h(-2)=-2(-2)^3+1$
$h (- 2) = 16 + 1 = 17$ $h(-2)=16+1=17$

let's substitute n by -2 n the second one
$g (- 2) = - (- 2) - 3$ $g(-2)=-(-2)-3$
$g (- 2) = - 1$ $g(-2)=-1$

then

$h (- 2) + g (- 2) = 17 - 1 = 16$ $h(-2)+g(-2)=17-1=16$

If h(n) = -2n^3 + 1h(n)=−2n3+1h(n) = -2n^3 + 1 and g(n) = -n-3g(n)=−n−3g(n) = -n-3, what is h(-2) + g(-2)h(−2)+g(−2)h(-2) + g(-2)?