If h(n) = -2n^3 + 1h(n)=2n3+1 and g(n) = -n-3g(n)=n3, what is h(-2) + g(-2)h(2)+g(2)?

1 Answer
Jun 5, 2016

16

Explanation:

let's substitute n by -2 in the first one
h(-2)=-2(-2)^3+1h(2)=2(2)3+1
h(-2)=16+1=17h(2)=16+1=17

let's substitute n by -2 n the second one
g(-2)=-(-2)-3g(2)=(2)3
g(-2)=-1g(2)=1

then

h(-2)+g(-2)=17-1=16h(2)+g(2)=171=16