What is $3a - (m-4n^2)$ when $a = -1, m = -3$ , and $n = 2$ ?

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Answer 1 · 2016-06-13T12:54:04

$16$

This involves substitution, but as soon as there are negative signs involved, work very carefully.

$a = -1, m = -3, n = 2$
$3a -(m - 4n^2) = 3(-1) - [(-3)-(4(2)^2)]$

$= -3 - [-3 - 4xx4)]$

$= -3 - [-19] = -3 +19$

$=16$

What is 3a - (m-4n^2)3a - (m-4n^2) when a = -1, m = -3a = -1, m = -3, and n = 2n = 2?