What is the standard form of $y = - 3 {(x - 1)}^{2} - 1$ $y=-3(x-1)^2-1$ ?

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Answer 1 · 2016-06-28T19:07:00

Standard form is given in the form,

$y = a x^{2} + b x + c$ $y = ax^2 + bx + c$

So all you have to do is solve through the equation!

$y = - 3 (x^{2} - 2 x + 1) - 1$ $y = -3(x^2-2x+1)-1$

$y = - 3 x^{2} + 6 x - 3 - 1$ $y = -3x^2+6x-3-1$

$y = - 3 x^{2} + 6 x - 4$ $y = -3x^2+6x-4$

What is the standard form of y=−3(x−1)2−1y=-3(x-1)^2-1 ?