How do you write a quadratic equation in standard form with the given roots 8, -2?
1 Answer
Jul 16, 2016
Explanation:
(x-8)(x+2) = 0(x−8)(x+2)=0
x^2-6x -16=0x2−6x−16=0
(x-8)(x+2) = 0(x−8)(x+2)=0
x^2-6x -16=0x2−6x−16=0