How do you write a quadratic equation in standard form with the given roots 8, -2?

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How do you write a quadratic equation in standard form with the given roots 8, -2?

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Answer 1 · 2016-07-16T13:48:41

$x^{2} - 6 x - 16 = 0$ $x^2 - 6x -16=0$

Explanation:

$(x - 8)$ $(x-8)$ and $(x + 2)$ $(x+2)$ are the factors of that quadratic equation. Multiply these two factors to the get the required quadratic equation.

$(x - 8) (x + 2) = 0$ $(x-8)(x+2) = 0$

$x^{2} - 6 x - 16 = 0$ $x^2-6x -16=0$

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How do you write a quadratic equation in standard form with the given roots 8, -2?

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