How do you evaluate x2y+x2z for x=6,y=4, and z=2?

2 Answers
Jul 19, 2016

The answer will be 27.

Explanation:

Simply plug in the values and simplify:

624+622

=364+362

=918

=27

Jul 19, 2016

27.

Explanation:

x2y+x2z=x2(1y+1z)=x2(y+z)yz=62(42)(4)(2)=36(6)8=27.