Question

How do you find the value of the discriminant and determine the nature of the roots `x^2 + 3x = 40`?

Answer 1

HI,discriminant is
`b^2-4ac` for quadratic `ax^2`+bx+c=0

this can be
1.greater then zero
2.equal to zero
3.less than zero

It depends on the sign of `x^2` term
if `x^2` is positive `b^2-4ac`
thrn `b^2-4ac>=0`
hence
b=3 ,a=1
c=-40
then ....
9-4(1)(-40)= is the value of determinant