A(-2, -1), B(2, 2), C(-1, -4), D(3,-1)A(2,1),B(2,2),C(1,4),D(3,1). What is the length of ABAB and CDCD?

1 Answer

AB=5AB=5
CD=5CD=5

Explanation:

Given A(-2, -1)A(2,1) and B(2, 2)B(2,2) and C(-1, -4)C(1,4) and D(3, -1)D(3,1)

Distance ABAB

AB=sqrt((2--1)^2+(2--2)^2)=sqrt(3^2+4^2)=sqrt(9+16)=sqrt25=5AB=(21)2+(22)2=32+42=9+16=25=5

CD=sqrt((-1--4)^2+(3--1)^2)=sqrt((-3)^2+4^2)=sqrt(9+16)=sqrt25=5CD=(14)2+(31)2=(3)2+42=9+16=25=5

God bless....I hope the explanation is useful.