How do you solve $\frac{4}{9} (4 - 2 m) = 48$ $frac{4}{9} ( 4- 2m ) = 48$ ?

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How do you solve $\frac{4}{9} (4 - 2 m) = 48$ $frac{4}{9} ( 4- 2m ) = 48$ ?

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Answer 1 · 2016-09-13T16:35:45

$m = - 52$ $m=-52$

Explanation:

$\frac{4}{9} (4 - 2 m) = 48$ $4/9(4−2m)=48$

Multiplying both sides by $\frac{9}{4}$ $9/4$ , we get:
$4 - 2 m = 48 \cdot \frac{9}{4}$ $4-2m=48*9/4$
$4 - 2 m = 12 \cdot 9$ $4-2m=12*9$
$4 - 2 m = 108$ $4-2m=108$

Subtracting 4 from both sides, we get:
$- 2 m = 108 - 4$ $-2m=108-4$
$- 2 m = 104$ $-2m=104$

Dividing both sides by $- 2$ $-2$ , we get:
$m = \frac{104}{- 2}$ $m=104/-2$
$m = - 52$ $m=-52$

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How do you solve $\frac{4}{9} (4 - 2 m) = 48$ $frac{4}{9} ( 4- 2m ) = 48$ ?

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How do you solve 49(4−2m)=48frac{4}{9} ( 4- 2m ) = 48?

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How do you solve $\frac{4}{9} (4 - 2 m) = 48$ $frac{4}{9} ( 4- 2m ) = 48$ ?